Home

Site Map

Search

physics, astronomy, solar system, sun, earth,
                      moon, stability Roche limit, gravitation, tidal
                      force
GeoAstro
Applets

Astronomy
physics,
                    astronomy, solar system, sun, earth, moon, stability
                    Roche limit, gravitation, tidal force
Chaos Game
physics, astronomy, solar system, sun, earth,
                      moon, stability Roche limit, gravitation, tidal
                      force
Java
physics, astronomy, solar system, sun, earth,
                    moon, stability Roche limit, gravitation, tidal
                    force
Miscel-

laneous
physics, astronomy, solar system, sun, earth,
                      moon, stability Roche limit, gravitation, tidal
                      force
Physics Quiz
physics,
                    astronomy, solar system, sun, earth, moon, stability
                    Roche limit, gravitation, tidal force
Who is
Who ?

back to Astrophysics

  The Roche Limit

The Roche limit is the minimum orbital radius which is necessary for dust or particles to grow forming a moon, or necessary for an existing moon to remain internally stable. It is named after Édouard Roche (1820 – 1883).

Roche
                    Limit
 


Determining the Roche limit

Two particles (mass m, radius r) orbiting the planet (mass M) will be bound, if their mutual gravitational force

F = G*m*m/(2r)2

is greater than the difference of the gravitational forces ((tidal force) exerted by the body of mass M  on the particles at R-r and R+r

ΔF = F2 - F1 = G*m*M/(R-r)2 - G*m*M/(R+r)2

ΔF = (G*m*M/R2)*[1/(1-r/R)2 - 1/(1+r/R)2]

For m<<M (or r/R<<1):
1/(1-r/R)2 - 1/(1+r/R)2 1/(1-2r/R) - 1/(1+2r/R) 1+2r/R - (1-2r/R) = 4r/R

The Roche limit is given by the condition:
ΔF = F
(G*m*M/R2)*4r/R = G*m*m/(4r2)
M*4r/R3 = m/
(4r2)

R = r*(16*M/m)1/3 ≈ 2.5*
r*(M/m)1/3

Using the densities of the bodies m=
ρm*4π*r3/3 and M=ρM*4π*rM3/3:

R = r*(16*M/m)1/3 = rM*(16*ρM/ρm)1/3

In case of equal densities, ρM = ρm

R ≈ 2.5*rM


radius
density 
Roche limit
R
orbit radius
Earth
6.378 km
5,510 kg/m3
18,970 km
384,400 km
= 1/20 R
Moon

3,350 kg/m3



radius
density 
Roche limit
R
orbit radius
Sun
696,000 km
1,410 kg/m3
1,113,000 km
149,600,000 km
= 1/134 R
Earth

5,510 kg/m3

In the solar system the orbits of the Earth's moon and of the Earth are in a region of stability.

The Hill Sphere

An astronomical body's Hill sphere is the region in which it dominates the attraction of satellites. It is named after John William Hill (1812–1879).

Hill
                    sphere

Determining the Hill Sphere radius


The satellite or moon (mass
μ) is orbiting the star (mass M) with the same angular velocity ω at the distance R+r as the planet (mass m) at the distance R (permanent full moon position).

The equilibrum condition for the planet is:
m ω2 R = G m M/R2

ω2 = GM/R3

The satellite is dragged by the combined gravitational forces exerted by the star and the planet:

μ ω2 (R+r) = G μ M/(R+r)2 + G μ m/r2

Inserting ω2:

G μ M (R+r)/R3 = G μ M/(R+r)2 + G μ m/r2

M (R+r)/R3 = M/(R+r)2 + G m/r2

M (R+r)3 r2 = M R3 r2 m R3 (R+r)2

m R3 (R+r)2 = M r2 (R3+3R2r+3Rr2+r3) - M R3 r2

m R3 (R+r)2 = M r3 (3R2+3Rr+r2)

For r<<R: (R+r)2 R2, and 3Rr+r2 ≈ 0. The equation simplifies:

m R5 = 3 M r3 R2
m R33 M r3

r = R [m/(3M)]1/3


mass
orbit radius
Hill sphere
r
orbit radius
moon
Sun
1.99×1030 kg
149,600,000 km
1,496,000 km
384,400 km
= 1/4 r
Earth
5.97×1024 kg

Web Links

Roche limit (Wikipedia)

Hill sphere (Wikipedia)

 


Last update 2015, Jun 18